4x^2-80+279=253

Solution for 4x^2-80+279=253 equation:

4x^2-80+279=253

We move all terms to the left:

4x^2-80+279-(253)=0

We add all the numbers together, and all the variables

4x^2-54=0

a = 4; b = 0; c = -54;
Δ = b2-4ac
Δ = 02-4·4·(-54)
Δ = 864
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{864}=\sqrt{144*6}=\sqrt{144}*\sqrt{6}=12\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{6}}{2*4}=\frac{0-12\sqrt{6}}{8}
=-\frac{12\sqrt{6}}{8}
=-\frac{3\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{6}}{2*4}=\frac{0+12\sqrt{6}}{8}
=\frac{12\sqrt{6}}{8}
=\frac{3\sqrt{6}}{2}
$